![]() ![]() ![]() Why is 2 * (i * i) faster than 2 * i * i in Java?.Android Gradle 5.0 Update:Cause: .tooling.util.Error: Java: invalid target release: 11 - IntelliJ IDEA.Gradle: Could not determine java version from '11.0.2'.Why am I getting Unknown error in line 1 of pom.xml?.Has been compiled by a more recent version of the Java Runtime (class file version 57.0).IntelliJ: Error:java: error: release version 5 not supported.Maven dependencies are failing with a 501 error.Best way for storing Java application name and version properties.Got a NumberFormatException while trying to parse a text file for objects.Hadoop MapReduce: Strange Result when Storing Previous Value in Memory in a Reduce Class (Java).Two Page Login with Spring Security 3.2.x.strange error in my Animation Drawable.Cannot retrieve string(s) from preferences (settings).Read input from a JOptionPane.showInputDialog box.I need to know how to get my program to output the word i typed in and also the new rearranged word using a 2D array.Are all Spring Framework Java Configuration injection examples buggy?.String method cannot be found in a main class method.java doesn't run if structure inside of onclick listener.When to create variables (memory management).getting " (1) no such column: _id10 " error.My eclipse won't open, i download the bundle pack it keeps saying error log.How to split a string in two and store it in a field.How do I get some variable from another class in Java?.How to implement a simple scenario the OO way.How much should a function trust another function.Under what circumstances can I call findViewById with an Options Menu / Action Bar item?.Set set = list.stream().collect(Collectors.toSet()) Using Stream : Another way is to convert given list to stream, then stream to set :- // Creating a list of strings Adds all of the elements in the list to the target set Creating a set with the same number of members in the list List list = Arrays.asList("One", "Two", "Three", "Four") Īpache Commons Collections : You may also use the Commons Collections API to convert a List to a Set :- // Creating a list of strings Remember that, converting from List to Set will remove duplicates from collection because List supports duplicates but Set does not support duplicates in Java.ĭirect Conversion : The most common and simple way to convert a List to a Set // Creating a list of strings Note that more efficient implementations of Set and Map are available through Trove (and other locations). (Remember: Optimize later!) If time efficiency matters use a HashSet if space efficiency matters, look at TreeSet. If you're after sorting, then consider the TreeSet. So, if you just care about uniqueness, use the HashSet. This depends on either compareTo() (from the comparable interface) or compare() (from the comparator) to ensure uniqueness. If it doesn't then you may want to use a comparator: Set lSet = new TreeSet(someComparator) (For more on equality look here)Īn alternative that gives a sorted set is: new TreeSet(myList) ![]() In this case, duplication is identified using the. Will give you an unsorted set which doesn't have duplicates. I agree with sepp2k, but there are some other details that might matter: new HashSet(myList) ![]()
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